X^2+4x-13=x^2-2x+27

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Solution for X^2+4x-13=x^2-2x+27 equation: 



X^2+4X-13=X^2-2X+27

We move all terms to the left:

X^2+4X-13-(X^2-2X+27)=0

We get rid of parentheses

X^2-X^2+4X+2X-27-13=0

We add all the numbers together, and all the variables

6X-40=0

We move all terms containing X to the left, all other terms to the right

6X=40

X=40/6

X=6+2/3

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